Construct a 95% confidence interval of the population proportion using the given information.x = 45, n = 150The lower bound isThe upper bound is(Round to three decimal places as needed.)

Answer:95% confidence interval of the population proportion is  (0.227, 0.373) Step-by-step explanation:Confidence Interval can be calculated using p±ME where p is the population proportion ([tex]\frac{45}{150} =0.3[/tex]ME is the margin of error from the mean and margin of error (ME) around the mean can be found using the formulaME=[tex]\frac{z*\sqrt{p*(1-p)}}{\sqrt{N} }[/tex] where z is the corresponding statistic in 95% confidence level (1.96)p is the population proportion (0.3)N is the sample size (150) then ME=[tex]\frac{1.96*\sqrt{0.3*0.7}}{\sqrt{150} }[/tex] ≈ 0.073Then 95% confidence interval would be 0.3±0.073 or (0.227, 0.373)